What is the general solution for cos(x)=0.5149,0<= x<2pi ?

The general solution for cos(x)=0.5149,0<= x<2pi is x=1.02990…,x=5.25327…

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cos(x)=0.5149,0<= x<2pi

cos (x) = 0.5149, 0 \leq x < 2 π

x = 1.02990 \dots, x = 5.25327 \dots

Degrees

x = 59.00922 \dots^{\circ}, x = 300.99077 \dots^{\circ}

Solution steps

cos (x) = 0.5149, 0 \leq x < 2 π

Apply trig inverse properties

cos (x) = 0.5149

General solutions for

cos (x) = 0.5149

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.5149) + 2 πn, x = 2 π - arccos (0.5149) + 2 πn

x = arccos (0.5149) + 2 πn, x = 2 π - arccos (0.5149) + 2 πn

Solutions for the range

0 \leq x < 2 π

x = 1.02990 \dots, x = 5.25327 \dots

sin (θ) - 0.2 cos (θ) = 0.704

3 sin (x) = sin (x) - 1

1 - tan (- x) = sec (- x)

cos (2 x - a) = sin (3 x)

x, 2 cos (x) = 3

What is the general solution for cos(x)=0.5149,0<= x<2pi ?
The general solution for cos(x)=0.5149,0<= x<2pi is x=1.02990…,x=5.25327…