What is the general solution for sin(b)= 12/13 ?

The general solution for sin(b)= 12/13 is b=1.17600…+2pin,b=pi-1.17600…+2pin

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sin(b)= 12/13

sin (b) = \frac{12}{13}

b = 1.17600 \dots + 2 πn, b = π - 1.17600 \dots + 2 πn

Degrees

b = 67.38013 \dots^{\circ} + 36 0^{\circ} n, b = 112.61986 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (b) = \frac{12}{13}

Apply trig inverse properties

sin (b) = \frac{12}{13}

General solutions for

sin (b) = \frac{12}{13}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

b = arcsin (\frac{12}{13}) + 2 πn, b = π - arcsin (\frac{12}{13}) + 2 πn

b = arcsin (\frac{12}{13}) + 2 πn, b = π - arcsin (\frac{12}{13}) + 2 πn

Show solutions in decimal form

b = 1.17600 \dots + 2 πn, b = π - 1.17600 \dots + 2 πn

3 = 1 + sec (x)

3 sin^{2} (x) - 7 sin (x) = 6

2 sin (x) (cos (x) - sin (x)) + (cos (x) - sin (x)) = 0

2 cos^{2} (x) - sin^{2} (x) + 1 = 0

- 6 sin (t) + 6 cos (2 t) = 0

What is the general solution for sin(b)= 12/13 ?
The general solution for sin(b)= 12/13 is b=1.17600…+2pin,b=pi-1.17600…+2pin