What is the general solution for 2cos(a)+3=4 ?

The general solution for 2cos(a)+3=4 is a= pi/3+2pin,a=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(a)+3=4

2 cos (a) + 3 = 4

a = \frac{π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

Degrees

a = 6 0^{\circ} + 36 0^{\circ} n, a = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

2 cos (a) + 3 = 4

Move

3

to the right side

2 cos (a) + 3 = 4

Subtract

3

from both sides

2 cos (a) + 3 - 3 = 4 - 3

Simplify

2 cos (a) = 1

2 cos (a) = 1

Divide both sides by

2

2 cos (a) = 1

Divide both sides by

2

\frac{2 cos ( a )}{2} = \frac{1}{2}

Simplify

cos (a) = \frac{1}{2}

cos (a) = \frac{1}{2}

General solutions for

cos (a) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

a = \frac{π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

a = \frac{π}{3} + 2 πn, a = \frac{5 π}{3} + 2 πn

tan (x) cot (x) - 3 tan (x) = 0

cos (θ) = 0.139

- \frac{2 3}{3} = sec (θ)

1 sin (3 0^{\circ}) = 1.7 sin (θ)

sin (x) = \pm \frac{1}{2}

What is the general solution for 2cos(a)+3=4 ?
The general solution for 2cos(a)+3=4 is a= pi/3+2pin,a=(5pi)/3+2pin