What is the general solution for tan(x)=1,-2pi<= x<= 2pi ?

The general solution for tan(x)=1,-2pi<= x<= 2pi is x= pi/4 ,x=(5pi)/4 ,x=-(3pi)/4 ,x=-(7pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)=1,-2pi<= x<= 2pi

tan (x) = 1, - 2 π \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}, x = - \frac{3 π}{4}, x = - \frac{7 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}, x = - 13 5^{\circ}, x = - 31 5^{\circ}

Solution steps

tan (x) = 1, - 2 π \leq x \leq 2 π

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

- 2 π \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}, x = - \frac{3 π}{4}, x = - \frac{7 π}{4}

(- 4 cos (x) - 6 sin (x))^{2} - 20 sin^{2} (x) = 16

arccos (x) = arcsin (\frac{1}{4}) + arcsin (\frac{7}{8})

3 cot^{2} (2 t - \frac{3 π}{2}) = 1

3 cot (θ) - 2 = 0

sin (u) = \frac{5}{13}

What is the general solution for tan(x)=1,-2pi<= x<= 2pi ?
The general solution for tan(x)=1,-2pi<= x<= 2pi is x= pi/4 ,x=(5pi)/4 ,x=-(3pi)/4 ,x=-(7pi)/4