{
"query": {
"display": "$$2\\cos^{2}\\left(x\\right)=3\\cos\\left(x\\right)+2$$",
"symbolab_question": "EQUATION#2\\cos^{2}(x)=3\\cos(x)+2"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=\\frac{2π}{3}+2πn,x=\\frac{4π}{3}+2πn",
"degrees": "x=120^{\\circ }+360^{\\circ }n,x=240^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$2\\cos^{2}\\left(x\\right)=3\\cos\\left(x\\right)+2{\\quad:\\quad}x=\\frac{2π}{3}+2πn,\\:x=\\frac{4π}{3}+2πn$$",
"input": "2\\cos^{2}\\left(x\\right)=3\\cos\\left(x\\right)+2",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "2\\cos^{2}\\left(x\\right)=3\\cos\\left(x\\right)+2",
"result": "\\cos\\left(x\\right)=2,\\:\\cos\\left(x\\right)=-\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(x\\right)=u$$",
"result": "2u^{2}=3u+2"
},
{
"type": "interim",
"title": "$$2u^{2}=3u+2{\\quad:\\quad}u=2,\\:u=-\\frac{1}{2}$$",
"input": "2u^{2}=3u+2",
"steps": [
{
"type": "interim",
"title": "Move $$2\\:$$to the left side",
"input": "2u^{2}=3u+2",
"result": "2u^{2}-2=3u",
"steps": [
{
"type": "step",
"primary": "Subtract $$2$$ from both sides",
"result": "2u^{2}-2=3u+2-2"
},
{
"type": "step",
"primary": "Simplify",
"result": "2u^{2}-2=3u"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "Move $$3u\\:$$to the left side",
"input": "2u^{2}-2=3u",
"result": "2u^{2}-2-3u=0",
"steps": [
{
"type": "step",
"primary": "Subtract $$3u$$ from both sides",
"result": "2u^{2}-2-3u=3u-3u"
},
{
"type": "step",
"primary": "Simplify",
"result": "2u^{2}-2-3u=0"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c=0$$",
"result": "2u^{2}-3u-2=0"
},
{
"type": "interim",
"title": "Solve with the quadratic formula",
"input": "2u^{2}-3u-2=0",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-3\\right)\\pm\\:\\sqrt{\\left(-3\\right)^{2}-4\\cdot\\:2\\left(-2\\right)}}{2\\cdot\\:2}",
"steps": [
{
"type": "definition",
"title": "Quadratic Equation Formula:",
"text": "For a quadratic equation of the form $$ax^2+bx+c=0$$ the solutions are <br/>$${\\quad}x_{1,\\:2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}$$"
},
{
"type": "step",
"primary": "For $${\\quad}a=2,\\:b=-3,\\:c=-2$$",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-3\\right)\\pm\\:\\sqrt{\\left(-3\\right)^{2}-4\\cdot\\:2\\left(-2\\right)}}{2\\cdot\\:2}"
}
],
"meta": {
"interimType": "Solving The Quadratic Equation With Quadratic Formula Definition 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\sqrt{\\left(-3\\right)^{2}-4\\cdot\\:2\\left(-2\\right)}=5$$",
"input": "\\sqrt{\\left(-3\\right)^{2}-4\\cdot\\:2\\left(-2\\right)}",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-3\\right)\\pm\\:5}{2\\cdot\\:2}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\sqrt{\\left(-3\\right)^{2}+4\\cdot\\:2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-3\\right)^{2}=3^{2}$$"
],
"result": "=\\sqrt{3^{2}+4\\cdot\\:2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$4\\cdot\\:2\\cdot\\:2=16$$",
"result": "=\\sqrt{3^{2}+16}"
},
{
"type": "step",
"primary": "$$3^{2}=9$$",
"result": "=\\sqrt{9+16}"
},
{
"type": "step",
"primary": "Add the numbers: $$9+16=25$$",
"result": "=\\sqrt{25}"
},
{
"type": "step",
"primary": "Factor the number: $$25=5^{2}$$",
"result": "=\\sqrt{5^{2}}"
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{5^{2}}=5$$"
],
"result": "=5",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s77dtxLd9UeyppCvogsL4v8xo8YJJMq21DhvmKFx9fgtkAlilG71elit3w1IBbYN0PPMIzKJkow6rtuXltoCsjrqN6Hv6MoTMtvtU0IQwXdn8J9HDrbqRwJyIBoCY7JVoJrWtsflfjzKgQu80yQwgzBCS3daIZHtloJpe/PvtsyNI="
}
},
{
"type": "step",
"primary": "Separate the solutions",
"result": "{u}_{1}=\\frac{-\\left(-3\\right)+5}{2\\cdot\\:2},\\:{u}_{2}=\\frac{-\\left(-3\\right)-5}{2\\cdot\\:2}"
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-3\\right)+5}{2\\cdot\\:2}:{\\quad}2$$",
"input": "\\frac{-\\left(-3\\right)+5}{2\\cdot\\:2}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{3+5}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Add the numbers: $$3+5=8$$",
"result": "=\\frac{8}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:2=4$$",
"result": "=\\frac{8}{4}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{8}{4}=2$$",
"result": "=2"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7sieDD8tdoqGWFRBUAjqnxpKet2LMwfmuCAWeFteXWHQgJ/ZZA32ZInFBpDtxBfiKRcASOqRpLIeIyUBzgC+nUCr6EdYdh/n2c4DPMiuUGOLnd1TAgOBWmZVEULOgvgERx0ij68Lvr+79BVqXMQAj8w=="
}
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-3\\right)-5}{2\\cdot\\:2}:{\\quad}-\\frac{1}{2}$$",
"input": "\\frac{-\\left(-3\\right)-5}{2\\cdot\\:2}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{3-5}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Subtract the numbers: $$3-5=-2$$",
"result": "=\\frac{-2}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:2=4$$",
"result": "=\\frac{-2}{4}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{2}{4}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=-\\frac{1}{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7q2cS8hAG+/7rXt5n0OkHv5Ket2LMwfmuCAWeFteXWHQgJ/ZZA32ZInFBpDtxBfiKmWiTEpQjat3SO7/l2m58l6mNsLv4gXj0VPO6vgHds8nFyoUUXuvn7kSsC/X/60sU0X9/eS2Lc0uU8wmW0XB2so8BPOx0wlsgFN8qUa6AzA0="
}
},
{
"type": "step",
"primary": "The solutions to the quadratic equation are:",
"result": "u=2,\\:u=-\\frac{1}{2}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(x\\right)$$",
"result": "\\cos\\left(x\\right)=2,\\:\\cos\\left(x\\right)=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(x\\right)=2{\\quad:\\quad}$$No Solution",
"input": "\\cos\\left(x\\right)=2",
"steps": [
{
"type": "step",
"primary": "$$-1\\le\\cos\\left(x\\right)\\le1$$",
"result": "\\mathrm{No\\:Solution}"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(x\\right)=-\\frac{1}{2}{\\quad:\\quad}x=\\frac{2π}{3}+2πn,\\:x=\\frac{4π}{3}+2πn$$",
"input": "\\cos\\left(x\\right)=-\\frac{1}{2}",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(x\\right)=-\\frac{1}{2}$$",
"result": "x=\\frac{2π}{3}+2πn,\\:x=\\frac{4π}{3}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "x=\\frac{2π}{3}+2πn,\\:x=\\frac{4π}{3}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=\\frac{2π}{3}+2πn,\\:x=\\frac{4π}{3}+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "2\\cos^{2}(x)-3\\cos(x)-2"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Move to the left side
Subtract from both sides
Simplify
Move to the left side
Subtract from both sides
Simplify
Write in the standard form
Solve with the quadratic formula
Quadratic Equation Formula:
For
Apply rule
Apply exponent rule: if is even
Multiply the numbers:
Add the numbers:
Factor the number:
Apply radical rule:
Separate the solutions
Apply rule
Add the numbers:
Multiply the numbers:
Divide the numbers:
Apply rule
Subtract the numbers:
Multiply the numbers:
Apply the fraction rule:
Cancel the common factor:
The solutions to the quadratic equation are:
Substitute back
No Solution
General solutions for
periodicity table with cycle:
Combine all the solutions
Graph
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Frequently Asked Questions (FAQ)
What is the general solution for 2cos^2(x)=3cos(x)+2 ?
The general solution for 2cos^2(x)=3cos(x)+2 is x=(2pi)/3+2pin,x=(4pi)/3+2pin