{
"query": {
"display": "$$\\sin\\left(2x\\right)=0,\\:-π\\le\\:x\\le\\:π$$",
"symbolab_question": "EQUATION#\\sin(2x)=0,-π\\le x\\le π"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=0,x=\\frac{π}{2},x=π,x=-π,x=-\\frac{π}{2}",
"degrees": "x=0^{\\circ },x=90^{\\circ },x=180^{\\circ },x=-180^{\\circ },x=-90^{\\circ }",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sin\\left(2x\\right)=0,\\:-π\\le\\:x\\le\\:π{\\quad:\\quad}x=0,\\:x=\\frac{π}{2},\\:x=π,\\:x=-π,\\:x=-\\frac{π}{2}$$",
"input": "\\sin\\left(2x\\right)=0,\\:-π\\le\\:x\\le\\:π",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\sin\\left(2x\\right)=0$$",
"result": "2x=0+2πn,\\:2x=π+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\sin\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sin(x)&x&\\sin(x)\\\\\\hline 0&0&π&0\\\\\\hline \\frac{π}{6}&\\frac{1}{2}&\\frac{7π}{6}&-\\frac{1}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{4π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{2}&1&\\frac{3π}{2}&-1\\\\\\hline \\frac{2π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{5π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{3π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&\\frac{1}{2}&\\frac{11π}{6}&-\\frac{1}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "2x=0+2πn,\\:2x=π+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions sin 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$2x=0+2πn:{\\quad}x=πn$$",
"input": "2x=0+2πn",
"steps": [
{
"type": "step",
"primary": "$$0+2πn=2πn$$",
"result": "2x=2πn"
},
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=2πn",
"result": "x=πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{2πn}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "x=πn"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$2x=π+2πn:{\\quad}x=\\frac{π}{2}+πn$$",
"input": "2x=π+2πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=π+2πn",
"result": "x=\\frac{π}{2}+πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{π}{2}+\\frac{2πn}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "x=\\frac{π}{2}+πn"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "x=πn,\\:x=\\frac{π}{2}+πn"
},
{
"type": "step",
"primary": "Solutions for the range $$-π\\le\\:x\\le\\:π$$",
"result": "x=0,\\:x=\\frac{π}{2},\\:x=π,\\:x=-π,\\:x=-\\frac{π}{2}"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "\\sin(2x),-π\\le x\\le π"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
General solutions for
periodicity table with cycle:
Solve
Divide both sides by
Divide both sides by
Simplify
Solve
Divide both sides by
Divide both sides by
Simplify
Solutions for the range
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for sin(2x)=0,-pi<= x<= pi ?
The general solution for sin(2x)=0,-pi<= x<= pi is x=0,x= pi/2 ,x=pi,x=-pi,x=-pi/2