What is the general solution for solvefor x,h=tan(x-pi/4) ?

The general solution for solvefor x,h=tan(x-pi/4) is x=arctan(h)+pin+pi/4

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solvefor x,h=tan(x-pi/4)

solve for

x, h = tan (x - \frac{π}{4})

x = arctan (h) + πn + \frac{π}{4}

Solution steps

h = tan (x - \frac{π}{4})

Switch sides

tan (x - \frac{π}{4}) = h

Apply trig inverse properties

tan (x - \frac{π}{4}) = h

General solutions for

tan (x - \frac{π}{4}) = h

tan (x) = a \Rightarrow x = arctan (a) + πn

x - \frac{π}{4} = arctan (h) + πn

x - \frac{π}{4} = arctan (h) + πn

Solve

x - \frac{π}{4} = arctan (h) + πn : x = arctan (h) + πn + \frac{π}{4}

x - \frac{π}{4} = arctan (h) + πn

Move

\frac{π}{4}

to the right side

x - \frac{π}{4} = arctan (h) + πn

Add

\frac{π}{4}

to both sides

x - \frac{π}{4} + \frac{π}{4} = arctan (h) + πn + \frac{π}{4}

Simplify

x = arctan (h) + πn + \frac{π}{4}

x = arctan (h) + πn + \frac{π}{4}

x = arctan (h) + πn + \frac{π}{4}

cos^{3} (x) + sin (x) = 0

12 cos^{2} (θ) + 5 sin (θ) - 9 = 0

cos^{2} (x) + cos (x) - 5 = - 3

\frac{9}{2} cos^{2} (x) - 2 = 0

\frac{1}{2} = cos (3 x)

What is the general solution for solvefor x,h=tan(x-pi/4) ?
The general solution for solvefor x,h=tan(x-pi/4) is x=arctan(h)+pin+pi/4