What is the general solution for m(0)=sin(2x)+2 ?

The general solution for m(0)=sin(2x)+2 is No Solution for x\in\mathbb{R}

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m(0)=sin(2x)+2

m (0) = sin (2 x) + 2

No Solution for x \in R

Solution steps

m (0) = sin (2 x) + 2

Switch sides

sin (2 x) + 2 = m \cdot 0

Apply rule

0 \cdot a = 0

sin (2 x) + 2 = 0

Move

2

to the right side

sin (2 x) + 2 = 0

Subtract

2

from both sides

sin (2 x) + 2 - 2 = 0 - 2

Simplify

sin (2 x) = - 2

sin (2 x) = - 2

- 1 \leq sin (x) \leq 1

No Solution for x \in R

6 cos^{2} (x) + cos (x) - 1 = 0

sin^{2} (x) + 2 cos (x) + 2 = 0

6 sin^{2} (x) - 5 cos (x) - 2 = 0

sin (θ) + cos (θ) = \frac{3}{5}

sec (x) - 4 = 0

What is the general solution for m(0)=sin(2x)+2 ?
The general solution for m(0)=sin(2x)+2 is No Solution for x\in\mathbb{R}