{
"query": {
"display": "$$4\\cos^{2}\\left(2x\\right)=3$$",
"symbolab_question": "EQUATION#4\\cos^{2}(2x)=3"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=\\frac{π}{12}+πn,x=\\frac{11π}{12}+πn,x=\\frac{5π}{12}+πn,x=\\frac{7π}{12}+πn",
"degrees": "x=15^{\\circ }+180^{\\circ }n,x=165^{\\circ }+180^{\\circ }n,x=75^{\\circ }+180^{\\circ }n,x=105^{\\circ }+180^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$4\\cos^{2}\\left(2x\\right)=3{\\quad:\\quad}x=\\frac{π}{12}+πn,\\:x=\\frac{11π}{12}+πn,\\:x=\\frac{5π}{12}+πn,\\:x=\\frac{7π}{12}+πn$$",
"input": "4\\cos^{2}\\left(2x\\right)=3",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "4\\cos^{2}\\left(2x\\right)=3",
"result": "\\cos\\left(2x\\right)=\\frac{\\sqrt{3}}{2},\\:\\cos\\left(2x\\right)=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(2x\\right)=u$$",
"result": "4u^{2}=3"
},
{
"type": "interim",
"title": "$$4u^{2}=3{\\quad:\\quad}u=\\frac{\\sqrt{3}}{2},\\:u=-\\frac{\\sqrt{3}}{2}$$",
"input": "4u^{2}=3",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$4$$",
"input": "4u^{2}=3",
"result": "u^{2}=\\frac{3}{4}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$4$$",
"result": "\\frac{4u^{2}}{4}=\\frac{3}{4}"
},
{
"type": "step",
"primary": "Simplify",
"result": "u^{2}=\\frac{3}{4}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
},
{
"type": "step",
"primary": "For $$x^{2}=f\\left(a\\right)$$ the solutions are $$x=\\sqrt{f\\left(a\\right)},\\:\\:-\\sqrt{f\\left(a\\right)}$$"
},
{
"type": "step",
"result": "u=\\sqrt{\\frac{3}{4}},\\:u=-\\sqrt{\\frac{3}{4}}"
},
{
"type": "interim",
"title": "$$\\sqrt{\\frac{3}{4}}=\\frac{\\sqrt{3}}{2}$$",
"input": "\\sqrt{\\frac{3}{4}}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{\\frac{a}{b}}=\\frac{\\sqrt[n]{a}}{\\sqrt[n]{b}},\\:\\quad$$ assuming $$a\\ge0,\\:b\\ge0$$",
"result": "=\\frac{\\sqrt{3}}{\\sqrt{4}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "interim",
"title": "$$\\sqrt{4}=2$$",
"input": "\\sqrt{4}",
"result": "=\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Factor the number: $$4=2^{2}$$",
"result": "=\\sqrt{2^{2}}"
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{2^{2}}=2$$"
],
"result": "=2",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"interimType": "N/A"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7FJIkkmi1CWuhEmDQGlA0N481GBhaFmRuYU8ivCdOkRGrju+5Z51e/ZZSD3gRHwjBnvjDY21b5XBQ44AG3rKeoERJNpqBgWYJo7POzHRJNgWKy+4oc4WkS69iOkw+tuw7OdycaE+yHbER8Bud6bqjpd6vq8ch6QORd3MMFeFuyk+wiNrEngO+NNvZ9sqNu+2V"
}
},
{
"type": "interim",
"title": "$$-\\sqrt{\\frac{3}{4}}=-\\frac{\\sqrt{3}}{2}$$",
"input": "-\\sqrt{\\frac{3}{4}}",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\sqrt{\\frac{3}{4}}:{\\quad}\\frac{\\sqrt{3}}{2}$$",
"input": "\\sqrt{\\frac{3}{4}}",
"result": "=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{\\frac{a}{b}}=\\frac{\\sqrt[n]{a}}{\\sqrt[n]{b}},\\:\\quad$$ assuming $$a\\ge0,\\:b\\ge0$$",
"result": "=\\frac{\\sqrt{3}}{\\sqrt{4}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "interim",
"title": "$$\\sqrt{4}=2$$",
"input": "\\sqrt{4}",
"result": "=\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Factor the number: $$4=2^{2}$$",
"result": "=\\sqrt{2^{2}}"
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{2^{2}}=2$$"
],
"result": "=2",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"interimType": "N/A"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7xVDfakA4g1ZczTHh+Arxm/DDmuD5U4GDJIF9k+W0I1gJQJZuTAY5js+oqjdT8kslDa1hUvtzgBcwD7zey8pjX+7J0HqxMc0mt58lG7zw6WRrXh3OSOXhogkv14GjeoU6kzLzxByUErH9eEiuIkZhcyb97z4ciRBzgXtcnYl8cilurCc0v6+SezXpJu+Sddf4"
}
},
{
"type": "step",
"result": "u=\\frac{\\sqrt{3}}{2},\\:u=-\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(2x\\right)$$",
"result": "\\cos\\left(2x\\right)=\\frac{\\sqrt{3}}{2},\\:\\cos\\left(2x\\right)=-\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(2x\\right)=\\frac{\\sqrt{3}}{2}{\\quad:\\quad}x=\\frac{π}{12}+πn,\\:x=\\frac{11π}{12}+πn$$",
"input": "\\cos\\left(2x\\right)=\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(2x\\right)=\\frac{\\sqrt{3}}{2}$$",
"result": "2x=\\frac{π}{6}+2πn,\\:2x=\\frac{11π}{6}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "2x=\\frac{π}{6}+2πn,\\:2x=\\frac{11π}{6}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$2x=\\frac{π}{6}+2πn:{\\quad}x=\\frac{π}{12}+πn$$",
"input": "2x=\\frac{π}{6}+2πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=\\frac{π}{6}+2πn",
"result": "x=\\frac{π}{12}+πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{\\frac{π}{6}}{2}+\\frac{2πn}{2}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2x}{2}=\\frac{\\frac{π}{6}}{2}+\\frac{2πn}{2}",
"result": "x=\\frac{π}{12}+πn",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2x}{2}:{\\quad}x$$",
"input": "\\frac{2x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7wyZUoCmW9j1Yiq04nFm+Ei061ljBSPJeENOw2efoSWt2cZ6LAXMcKee6PSyjLEFrRSpN33oxZMojoqvYhvSJACLkpiVA7S8UT8ieezZKu6rogJeWDMKCUBljFmQOLy/H"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{\\frac{π}{6}}{2}+\\frac{2πn}{2}:{\\quad}\\frac{π}{12}+πn$$",
"input": "\\frac{\\frac{π}{6}}{2}+\\frac{2πn}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{\\frac{π}{6}}{2}=\\frac{π}{12}$$",
"input": "\\frac{\\frac{π}{6}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{\\frac{b}{c}}{a}=\\frac{b}{c\\:\\cdot\\:a}$$",
"result": "=\\frac{π}{6\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$6\\cdot\\:2=12$$",
"result": "=\\frac{π}{12}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7tiTmKkmeEqHWILbBb88ajWqCk54oAXku+C9eC3AYg+HNGoPE9TME3q+OPmgkv2RQV7wanvTgjKqnID/UMq66GyOk8ADv3Qq+ATrkEXcaomSIDZ1VqNwwAzGjxOWVq2SRIeT+01jSenFHVJVrApCtnrwW5Nhd3K/P3qgp381wL9s="
}
},
{
"type": "interim",
"title": "$$\\frac{2πn}{2}=πn$$",
"input": "\\frac{2πn}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=πn"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "=\\frac{π}{12}+πn"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7tiTmKkmeEqHWILbBb88ajXgE6C3CSriiKdwyx/Ba2X7Cl1oDQxTLS01lmG4qDSnCzRqDxPUzBN6vjj5oJL9kUFe8Gp704IyqpyA/1DKuuhu2zDrJYatHsKrXlsSOX1ji1sD7NfhsPe7eDHrmjY0mE8DwQcN28geUT7aUsumC7doaryAYIFbz6VGRGlOmTNL9ZTEpIsWx2g1tU2drz2Msym6sJzS/r5J7Nekm75J11/g="
}
},
{
"type": "step",
"result": "x=\\frac{π}{12}+πn"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
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}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$2x=\\frac{11π}{6}+2πn:{\\quad}x=\\frac{11π}{12}+πn$$",
"input": "2x=\\frac{11π}{6}+2πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=\\frac{11π}{6}+2πn",
"result": "x=\\frac{11π}{12}+πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{\\frac{11π}{6}}{2}+\\frac{2πn}{2}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2x}{2}=\\frac{\\frac{11π}{6}}{2}+\\frac{2πn}{2}",
"result": "x=\\frac{11π}{12}+πn",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2x}{2}:{\\quad}x$$",
"input": "\\frac{2x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7wyZUoCmW9j1Yiq04nFm+Ei061ljBSPJeENOw2efoSWt2cZ6LAXMcKee6PSyjLEFrRSpN33oxZMojoqvYhvSJACLkpiVA7S8UT8ieezZKu6rogJeWDMKCUBljFmQOLy/H"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{\\frac{11π}{6}}{2}+\\frac{2πn}{2}:{\\quad}\\frac{11π}{12}+πn$$",
"input": "\\frac{\\frac{11π}{6}}{2}+\\frac{2πn}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{\\frac{11π}{6}}{2}=\\frac{11π}{12}$$",
"input": "\\frac{\\frac{11π}{6}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{\\frac{b}{c}}{a}=\\frac{b}{c\\:\\cdot\\:a}$$",
"result": "=\\frac{11π}{6\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$6\\cdot\\:2=12$$",
"result": "=\\frac{11π}{12}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7tiTmKkmeEqHWILbBb88ajcm5FXQ50IQsy9V6MeVoA3UgJ/ZZA32ZInFBpDtxBfiKXYGCmiBF99lesmXZ9iIfJ4AbY1ZZlr0ES7ShAvPM/yhTW26qciuyUBGXQExCUedYvS8N5VCze8qz+LNUf5QAR8NqfIbgCoEQ5iqOpxvXCtHuJ1iXawr0xn/4zW2wj+oZ"
}
},
{
"type": "interim",
"title": "$$\\frac{2πn}{2}=πn$$",
"input": "\\frac{2πn}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=πn"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7YVyjdFRW0jf8Bxzp61JzqHyRHuGw7+tM5METTDj6vVECnBmppnUV+797UqKeeyBQmGP7cF4dEaUuqswlNsH4qzvxhqyDNGf7EUmy3SORhvXPUvVtHPbCNTQhn1k5UbDm"
}
},
{
"type": "step",
"result": "=\\frac{11π}{12}+πn"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7tiTmKkmeEqHWILbBb88aja8YN6VzLM/g2fVQvpHYB3AYKXMStDfJcV1gA+Z/JDXIICf2WQN9mSJxQaQ7cQX4il2BgpogRffZXrJl2fYiHyfmx8MSjQWWYpQEOqS7iNsYRSpN33oxZMojoqvYhvSJACLkpiVA7S8UT8ieezZKu6q99iKcg75ivhzP3grxubPxeAToLcJKuKIp3DLH8FrZfjkRYT57po0fVp+kBBk2foE="
}
},
{
"type": "step",
"result": "x=\\frac{11π}{12}+πn"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
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}
}
],
"meta": {
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"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "x=\\frac{π}{12}+πn,\\:x=\\frac{11π}{12}+πn"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(2x\\right)=-\\frac{\\sqrt{3}}{2}{\\quad:\\quad}x=\\frac{5π}{12}+πn,\\:x=\\frac{7π}{12}+πn$$",
"input": "\\cos\\left(2x\\right)=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(2x\\right)=-\\frac{\\sqrt{3}}{2}$$",
"result": "2x=\\frac{5π}{6}+2πn,\\:2x=\\frac{7π}{6}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "2x=\\frac{5π}{6}+2πn,\\:2x=\\frac{7π}{6}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$2x=\\frac{5π}{6}+2πn:{\\quad}x=\\frac{5π}{12}+πn$$",
"input": "2x=\\frac{5π}{6}+2πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=\\frac{5π}{6}+2πn",
"result": "x=\\frac{5π}{12}+πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{\\frac{5π}{6}}{2}+\\frac{2πn}{2}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2x}{2}=\\frac{\\frac{5π}{6}}{2}+\\frac{2πn}{2}",
"result": "x=\\frac{5π}{12}+πn",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2x}{2}:{\\quad}x$$",
"input": "\\frac{2x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=x"
}
],
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{
"type": "interim",
"title": "Simplify $$\\frac{\\frac{5π}{6}}{2}+\\frac{2πn}{2}:{\\quad}\\frac{5π}{12}+πn$$",
"input": "\\frac{\\frac{5π}{6}}{2}+\\frac{2πn}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{\\frac{5π}{6}}{2}=\\frac{5π}{12}$$",
"input": "\\frac{\\frac{5π}{6}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{\\frac{b}{c}}{a}=\\frac{b}{c\\:\\cdot\\:a}$$",
"result": "=\\frac{5π}{6\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$6\\cdot\\:2=12$$",
"result": "=\\frac{5π}{12}"
}
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{
"type": "interim",
"title": "$$\\frac{2πn}{2}=πn$$",
"input": "\\frac{2πn}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=πn"
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},
{
"type": "step",
"result": "=\\frac{5π}{12}+πn"
}
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{
"type": "interim",
"title": "Solve $$2x=\\frac{7π}{6}+2πn:{\\quad}x=\\frac{7π}{12}+πn$$",
"input": "2x=\\frac{7π}{6}+2πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2x=\\frac{7π}{6}+2πn",
"result": "x=\\frac{7π}{12}+πn",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2x}{2}=\\frac{\\frac{7π}{6}}{2}+\\frac{2πn}{2}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2x}{2}=\\frac{\\frac{7π}{6}}{2}+\\frac{2πn}{2}",
"result": "x=\\frac{7π}{12}+πn",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2x}{2}:{\\quad}x$$",
"input": "\\frac{2x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=x"
}
],
"meta": {
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},
{
"type": "interim",
"title": "Simplify $$\\frac{\\frac{7π}{6}}{2}+\\frac{2πn}{2}:{\\quad}\\frac{7π}{12}+πn$$",
"input": "\\frac{\\frac{7π}{6}}{2}+\\frac{2πn}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{\\frac{7π}{6}}{2}=\\frac{7π}{12}$$",
"input": "\\frac{\\frac{7π}{6}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{\\frac{b}{c}}{a}=\\frac{b}{c\\:\\cdot\\:a}$$",
"result": "=\\frac{7π}{6\\cdot\\:2}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$6\\cdot\\:2=12$$",
"result": "=\\frac{7π}{12}"
}
],
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},
{
"type": "interim",
"title": "$$\\frac{2πn}{2}=πn$$",
"input": "\\frac{2πn}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=πn"
}
],
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},
{
"type": "step",
"result": "=\\frac{7π}{12}+πn"
}
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}
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},
{
"type": "step",
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"result": "x=\\frac{π}{12}+πn,\\:x=\\frac{11π}{12}+πn,\\:x=\\frac{5π}{12}+πn,\\:x=\\frac{7π}{12}+πn"
}
],
"meta": {
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Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Divide both sides by
Divide both sides by
Simplify
For the solutions are
Apply radical rule: assuming
Factor the number:
Apply radical rule:
Simplify
Apply radical rule: assuming
Factor the number:
Apply radical rule:
Substitute back
General solutions for
periodicity table with cycle:
Solve
Divide both sides by
Divide both sides by
Simplify
Simplify
Divide the numbers:
Simplify
Apply the fraction rule:
Multiply the numbers:
Divide the numbers:
Solve
Divide both sides by
Divide both sides by
Simplify
Simplify
Divide the numbers:
Simplify
Apply the fraction rule:
Multiply the numbers:
Divide the numbers:
General solutions for
periodicity table with cycle:
Solve
Divide both sides by
Divide both sides by
Simplify
Simplify
Divide the numbers:
Simplify
Apply the fraction rule:
Multiply the numbers:
Divide the numbers:
Solve
Divide both sides by
Divide both sides by
Simplify
Simplify
Divide the numbers:
Simplify
Apply the fraction rule:
Multiply the numbers:
Divide the numbers:
Combine all the solutions