What is the general solution for solvefor u,sin(u)=x ?

The general solution for solvefor u,sin(u)=x is u=arcsin(x)+2pin,u=pi+arcsin(-x)+2pin

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solvefor u,sin(u)=x

solve for

u, sin (u) = x

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

Solution steps

sin (u) = x

Apply trig inverse properties

sin (u) = x

General solutions for

sin (u) = x

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

sin^{2} (x) - sin (x) - 6 = 0

cos (z) = sin (z)

sin (x + 3) = sin (x)

4 sin^{2} (x) = \frac{csc ^{2} ( x )}{4}

2 sin (3 x) = 2

What is the general solution for solvefor u,sin(u)=x ?
The general solution for solvefor u,sin(u)=x is u=arcsin(x)+2pin,u=pi+arcsin(-x)+2pin