What is the general solution for 2cos(5x)=9 ?

The general solution for 2cos(5x)=9 is No Solution for x\in\mathbb{R}

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2cos(5x)=9

2 cos (5 x) = 9

No Solution for x \in R

Solution steps

2 cos (5 x) = 9

Divide both sides by

2

2 cos (5 x) = 9

Divide both sides by

2

\frac{2 cos ( 5 x )}{2} = \frac{9}{2}

Simplify

cos (5 x) = \frac{9}{2}

cos (5 x) = \frac{9}{2}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

- 5 cos (c) - 1 = 2 cos (c) + 3

3 tan (t) - cot (t) - 5 = 0

tan^{2} (x) - 5 tan (x) - 9 = 0

arctan (t) = \frac{π}{4}

tan (\frac{π}{2} - θ) = cos (- θ)

What is the general solution for 2cos(5x)=9 ?
The general solution for 2cos(5x)=9 is No Solution for x\in\mathbb{R}