What is the general solution for 3tan(θ)-sqrt(3)=0 ?

The general solution for 3tan(θ)-sqrt(3)=0 is θ= pi/6+pin

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3tan(θ)-sqrt(3)=0

3 tan (θ) - 3 = 0

θ = \frac{π}{6} + πn

Degrees

θ = 3 0^{\circ} + 18 0^{\circ} n

Solution steps

3 tan (θ) - 3 = 0

Move

3

to the right side

3 tan (θ) - 3 = 0

Add

3

to both sides

3 tan (θ) - 3 + 3 = 0 + 3

Simplify

3 tan (θ) = 3

3 tan (θ) = 3

Divide both sides by

3

3 tan (θ) = 3

Divide both sides by

3

\frac{3 tan ( θ )}{3} = \frac{3}{3}

Simplify

tan (θ) = \frac{3}{3}

tan (θ) = \frac{3}{3}

General solutions for

tan (θ) = \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{6} + πn

θ = \frac{π}{6} + πn

cot (θ) = \frac{1}{cot ( θ )}

(tan (x))^{5} - 9 tan (x) = 0

2 cot^{2} (x) + 2 csc^{2} (x) = 1 + 4 csc (x)

sin (2 θ) = cos (θ), 0 \leq θ < 2 π

\frac{3}{2} sec (θ) = 3

What is the general solution for 3tan(θ)-sqrt(3)=0 ?
The general solution for 3tan(θ)-sqrt(3)=0 is θ= pi/6+pin