What is the general solution for cos(θ)= 2/3 ,-(5pi)/2 ,2pi ?

The general solution for cos(θ)= 2/3 ,-(5pi)/2 ,2pi is No Solution for θ\in\mathbb{R}

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cos(θ)= 2/3 ,-(5pi)/2 ,2pi

cos (θ) = \frac{2}{3}, - \frac{5 π}{2}, 2 π

No Solution for θ \in R

Solution steps

cos (θ) = \frac{2}{3}, - \frac{5 π}{2}, 2 π

Apply trig inverse properties

cos (θ) = \frac{2}{3}

General solutions for

cos (θ) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

Solutions for the range

- \frac{5 π}{2}

No Solution for θ \in R

6 cos (2 x) = 32

2 cos^{2} (x) - sin^{2} (x) = 0

10 cos (x) + 4 = 10

x, arctan (x) = \frac{π}{4}

cos (2 θ) + 3 cos (θ) = 1

What is the general solution for cos(θ)= 2/3 ,-(5pi)/2 ,2pi ?
The general solution for cos(θ)= 2/3 ,-(5pi)/2 ,2pi is No Solution for θ\in\mathbb{R}