What is the general solution for sin(θ)= 5/6 ,cos(θ) ?

The general solution for sin(θ)= 5/6 ,cos(θ) is No Solution for θ\in\mathbb{R}

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sin(θ)= 5/6 ,cos(θ)

sin (θ) = \frac{5}{6}, cos (θ)

No Solution for θ \in R

Solution steps

sin (θ) = \frac{5}{6}, cos (θ)

Apply trig inverse properties

sin (θ) = \frac{5}{6}

General solutions for

sin (θ) = \frac{5}{6}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{5}{6}) + 2 πn, θ = π - arcsin (\frac{5}{6}) + 2 πn

θ = arcsin (\frac{5}{6}) + 2 πn, θ = π - arcsin (\frac{5}{6}) + 2 πn

Solutions for the range

cos (θ)

No Solution for θ \in R

tan^{2} (t) - sec^{2} (t) = 1

sin (x) tan (x) = \frac{1}{cot ( x )}

0 = - 2 sin (x) - 1

x, z = sin (2 x + 3 y)

2 sin (3 θ) = 2

What is the general solution for sin(θ)= 5/6 ,cos(θ) ?
The general solution for sin(θ)= 5/6 ,cos(θ) is No Solution for θ\in\mathbb{R}