What is the value of -2sqrt(2)sin((-pi)/4) ?

The value of -2sqrt(2)sin((-pi)/4) is 2

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-2sqrt(2)sin((-pi)/4)

- 22 sin (\frac{- π}{4})

2

Solution steps

- 22 sin (\frac{- π}{4})

Rewrite using trig identities:

sin (\frac{- π}{4}) = - \frac{2}{2}

sin (\frac{- π}{4})

Simplify

= sin (- \frac{π}{4})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{π}{4}) = - sin (\frac{π}{4})

= - sin (\frac{π}{4})

Use the following trivial identity:

sin (\frac{π}{4}) = \frac{2}{2}

sin (\frac{π}{4})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= - \frac{2}{2}

= - 22 (- \frac{2}{2})

Simplify

- 22 (- \frac{2}{2}) : 2

- 22 (- \frac{2}{2})

Apply rule

- (- a) = a

= 22 \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 2 2}{2}

Cancel the common factor:

2

= 22

Apply radical rule:

a a = a

22 = 2

= 2

= 2

\frac{50}{sin ( 5 )}

arctan (\frac{8.29}{14.44})

sin^{2} (1 2^{\circ}) - cos^{2} (1 2^{\circ})

csc (\frac{17 π}{3})

- 4 sin (\frac{π}{4}) + 4 cos (\frac{π}{4})

What is the value of -2sqrt(2)sin((-pi)/4) ?
The value of -2sqrt(2)sin((-pi)/4) is 2