What is the value of -8*4^2cos(4^2-2*4*2)-15*2^2 ?

The value of -8*4^2cos(4^2-2*4*2)-15*2^2 is -188

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-84^2cos(4^2-242)-152^2

- 8 \cdot 4^{2} cos (4^{2} - 2 \cdot 4 \cdot 2) - 15 \cdot 2^{2}

- 188

Solution steps

- 8 \cdot 4^{2} cos (4^{2} - 2 \cdot 4 \cdot 2) - 15 \cdot 2^{2}

Simplify

= - 128 cos (0) - 60

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= - 128 \cdot 1 - 60

Simplify

= - 188

arcsin (0.494)

tan (32. 3^{\circ})

arctan (\frac{15}{14})

(csc (4 5^{\circ})) (sec (4 5^{\circ}))

sin^{2} (3) - sin^{2} (2)

What is the value of -8*4^2cos(4^2-2*4*2)-15*2^2 ?
The value of -8*4^2cos(4^2-2*4*2)-15*2^2 is -188