What is the value of tan(60)+2tan(30) ?

The value of tan(60)+2tan(30) is sqrt(3)+(2sqrt(3))/3

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tan(60)+2tan(30)

tan (6 0^{\circ}) + 2 tan (3 0^{\circ})

3 + \frac{2 3}{3}

Decimal Notation

2.88675 \dots

Solution steps

tan (6 0^{\circ}) + 2 tan (3 0^{\circ})

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

Use the following trivial identity:

tan (3 0^{\circ}) = \frac{3}{3}

tan (3 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= \frac{3}{3}

= 3 + 2 \cdot \frac{3}{3}

Simplify

3 + 2 \cdot \frac{3}{3} : 3 + \frac{2 3}{3}

3 + 2 \cdot \frac{3}{3}

Multiply

2 \cdot \frac{3}{3} : \frac{2 3}{3}

2 \cdot \frac{3}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 2}{3}

= 3 + \frac{2 3}{3}

= 3 + \frac{2 3}{3}

\frac{18}{cos ( 43. 4 ^{\circ} )}

arcsinh (2 π)

arctan (\frac{8}{7.8})

arctan (\frac{70}{25})

- 3 cos (- \frac{π}{6}) - 4 tan (- \frac{π}{6})

What is the value of tan(60)+2tan(30) ?
The value of tan(60)+2tan(30) is sqrt(3)+(2sqrt(3))/3