What is (-3)^2+6(-3)(4) ?

The solution to (-3)^2+6(-3)(4) is -63

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(-3)^2+6(-3)(4)

(- 3)^{2} + 6 (- 3) (4)

- 63

Solution steps

(- 3)^{2} + 6 (- 3) (4)

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 6 (- 3) (4)

Multiply and divide (left to right)

6 (- 3) (4) : 72

6 (- 3) (4)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 3) = - 6 \cdot 3 = - 18

= - 18 (4)

18 (4) = 72

18 (4)

Apply rule:

(a) = a

(4) = 4

= 18 \cdot 4

Multiply the numbers:

18 \cdot 4 = 72

= 72

= 72

= 9 - 72

Add and subtract (left to right)

9 - 72 : - 63

9 - 72

9 - 72 = - 63

= - 63

= - 63

5 (4)^{1}

432 - 28 - 30 - 15

- 3 + 16 - 7 + 4

2 + 6 \div 2 \times 3

(3 + 9)^{2}