{
"query": {
"display": "lcm $$6,\\:9$$",
"symbolab_question": "PRE_ALGEBRA#lcm 6,9"
},
"solution": {
"level": "PERFORMED",
"subject": "Pre Algebra",
"topic": "Factors & Primes",
"subTopic": "LCM",
"default": "18",
"meta": {
"showVerify": true
}
},
"methods": [
{
"method": "Solve using prime factors",
"query": {
"display": "lcm by prime factors $$6,\\:9$$",
"symbolab_question": "lcmfact 6,9"
}
},
{
"method": "Solve using multipliers",
"query": {
"display": "lcm by multipliers $$6,\\:9$$",
"symbolab_question": "lcmmult 6,9"
}
},
{
"method": "Solve using GCD",
"query": {
"display": "lcm by gcd $$6,\\:9$$",
"symbolab_question": "lcmgcd 6,9"
}
}
],
"steps": {
"type": "interim",
"title": "Least Common Multiplier of $$6,\\:9:{\\quad}18$$",
"input": "6,\\:9",
"steps": [
{
"type": "definition",
"title": "Least Common Multiplier (LCM)",
"text": "The LCM of $$a,\\:b$$ is the smallest positive number that is divisible by both $$a$$ and $$b$$"
},
{
"type": "interim",
"title": "Prime factorization of $$6:{\\quad}2\\cdot\\:3$$",
"input": "6",
"steps": [
{
"type": "step",
"primary": "$$6\\:$$divides by $$2\\quad\\:6=3\\cdot\\:2$$",
"result": "=2\\cdot\\:3"
},
{
"type": "step",
"primary": "$$2,\\:3$$ are all prime numbers, therefore no further factorization is possible",
"result": "=2\\cdot\\:3"
}
],
"meta": {
"solvingClass": "Composite Integer",
"interimType": "Prime Fac 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xyoU2cWyPLDgE1QLLHeauuc3PHQdChPJ2JhfqHT+ZU0OMrfn8NOj0LUzuzje6xTyxRuUHkFwKrCGUG/pR2kioRow/y9DKGIPglJ+qMi9xDu2KE1OovxZAaXg7BtrFPk4UcCzRnGgMN6CYRfod7Mq0dp1AjXz67i9oO9i25G22wINi"
}
},
{
"type": "interim",
"title": "Prime factorization of $$9:{\\quad}3\\cdot\\:3$$",
"input": "9",
"steps": [
{
"type": "step",
"primary": "$$9\\:$$divides by $$3\\quad\\:9=3\\cdot\\:3$$",
"result": "=3\\cdot\\:3"
}
],
"meta": {
"solvingClass": "Composite Integer",
"interimType": "Prime Fac 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xyoU2cWyPLDgE1QLLHeauuc3PHQdChPJ2JhfqHT+ZU0OMrfn8NOj0LUzuzje6xTyxRjcq2F6aCU5dakzncJqkgGc/y9DKGIPglJ+qMi9xDu2KE1OovxZAaXg7BtrFPk4UcCzRnGgMN6CYRfod7Mq0dp02ygGGsmIGE3wDrLHDVisx"
}
},
{
"type": "step",
"primary": "Multiply each factor the greatest number of times it occurs in either $$6$$ or $$9$$",
"result": "=2\\cdot\\:3\\cdot\\:3"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:3\\cdot\\:3=18$$",
"result": "=18"
}
],
"meta": {
"solvingClass": "LCM"
}
},
"meta": {
"showVerify": true
}
}
Solution
lcm
Solution
Solution steps
Prime factorization of
divides by
are all prime numbers, therefore no further factorization is possible
Prime factorization of
divides by
Multiply each factor the greatest number of times it occurs in either or
Multiply the numbers:
Popular Examples
Frequently Asked Questions (FAQ)
What is lcm 6,9 ?
The solution to lcm 6,9 is 18
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