What is longmult 21*15 ?

The solution to longmult 21*15 is 315

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Evaluate 21*15

long multiplication

21 \cdot 15

315

Solution steps

21 \cdot 15

Line up the numbers

\times 2115

Multiply the top number by the bottom number one digit at a time starting with the ones digit (from right to left)

Multiply the top number by the bolded digit of the bottom number

\times 2115

Mutliply the bold numbers:

1 \cdot 5 = 5

\frac{\times 2 1 1 5}{5}

Mutliply the bold numbers:

2 \cdot 5 = 10

Carry

1

to the column on the left and write

0

in the result line

\frac{\times 1 2 1 1 5}{0 5}

Add the carried digit,

1

, to the result

\frac{\times 1 2 1 1 5}{1 0 5}

Multiply the top number by the bolded digit of the bottom number

\frac{\times 2 1 1 5}{1 0 5}

Mutliply the bold numbers:

1 \cdot 1 = 1

\frac{\times 2 1 1 5}{1 0 1 5}

Mutliply the bold numbers:

2 \cdot 1 = 2

\frac{\times 2 1 1 5}{1 2 0 1 5}

Add the rows to get the answer. For simplicity, fill in trailing zeros

\frac{\times 2 1 1 5}{1 2 0 1 5 0}

105 + 210 = 315

+ 120150

Add the digits of the bolded column:

5 + 0 = 5

\frac{+ 1 2 0 1 5 0}{+ 5}

Add the digits of the bolded column:

0 + 1 = 1

\frac{+ 1 2 0 1 5 0}{+ 1 5}

Add the digits of the bolded column:

1 + 2 = 3

\frac{+ 1 2 0 1 5 0}{+ 3 1 5}

= 315

= 315

t h e \frac{57}{76}

(1/5) /100

150 \cdot 6

208

33.33