What is the axis y=(x-6)(x-5) ?

The axis y=(x-6)(x-5) is x= 11/2

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axis y=(x-6)(x-5)

axis

y = (x - 6) (x - 5)

x = \frac{11}{2}

Solution steps

y = (x - 6) (x - 5)

Rewrite

y = (x - 6) (x - 5)

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - \frac{11}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{11}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{11}{2}

(x + 1)^{2} = 2 (y + 2)

y = x^{2} + 81

(y - 1)^{2} = - 16 (x - 1)

y = \frac{- 7 + 2 x ^{2} - 4 x}{3}

y = x^{2} - 10 x - 7