What is the axis x^2+y=4 ?

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axis x^2+y=4

axis

x^{2} + y = 4

x = 0

Solution steps

x^{2} + y = 4

Rewrite

x^{2} + y = 4

in the standard form:

4 (- \frac{1}{4}) (y - 4) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 4), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = - x (x + 6)

- x^{2} - 10 x - 25

y = (x + 8) (x - 8)

y = - x^{2} - x + 6

(x - 1)^{2} = - 20 (y - 4)