What is the axis y=-x^2+6x+2 ?

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axis y=-x^2+6x+2

axis

y = - x^{2} + 6 x + 2

x = 3

Solution steps

y = - x^{2} + 6 x + 2

Rewrite

y = - x^{2} + 6 x + 2

in the standard form

4 (- \frac{1}{4}) (y - 11) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 11), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = (x - 3) (x - 7)

- 2 x^{2} + 24 x + y - 70 = 0

+ y^{2} = 4 x

y = (x + 2) (x - 3)

x = (- y - 1) (y + 3)