What is the axis y=(2-x)^2 ?

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axis y=(2-x)^2

axis

y = (2 - x)^{2}

x = 2

Solution steps

y = (2 - x)^{2}

Rewrite

y = (2 - x)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = x^{2} + 16 x + 60

y = 6 - x - x^{2}

x = y^{2} - 6

y = 40 (x - 1) + 6 - 33 (1 - \frac{x}{0.4})^{2}

y = \frac{1}{4} (x - 10)^{2} - 1