What is the axis y=-3x^2-12x-5 ?

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axis y=-3x^2-12x-5

axis

y = - 3 x^{2} - 12 x - 5

x = - 2

Solution steps

y = - 3 x^{2} - 12 x - 5

Rewrite

y = - 3 x^{2} - 12 x - 5

in the standard form

4 (- \frac{1}{12}) (y - 7) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 7), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = x^{2} - 5

x^{2}

y = - \frac{1}{4} x^{2} + 8 x - 4

y = x^{2} - 10 x + 23

y^{2} + 8 x - 4 y + 20 = 0