What is the axis y=(x+1)(x+2) ?

The axis y=(x+1)(x+2) is x=-3/2

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axis y=(x+1)(x+2)

axis

y = (x + 1) (x + 2)

x = - \frac{3}{2}

Solution steps

y = (x + 1) (x + 2)

Rewrite

y = (x + 1) (x + 2)

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

y = x^{2} + x - 12

x = y^{2} - 2

y = x^{2} - 8 x + 7

(x - 5)^{2} = - 70 (y - 1)

y^{2} = 3 x