What is the axis (x+2)^2=-12(y-5) ?

The axis (x+2)^2=-12(y-5) is x=-2

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axis (x+2)^2=-12(y-5)

axis

(x + 2)^{2} = - 12 (y - 5)

x = - 2

Solution steps

(x + 2)^{2} = - 12 (y - 5)

Rewrite

(x + 2)^{2} = - 12 (y - 5)

in the standard form:

4 (- 3) (y - 5) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 5), p = - 3

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = x (x - 4)

y^{2} - x + 8 y + 13 = 0

y = 7 x^{2} - 9 x - 5

y = x^{2} - 6 x + 10

y = - 0.23 x^{2} + 1.87 x + 1.5