What is the directrix-8x^2 ?

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directrix-8x^2

directrix

- 8 x^{2}

y = \frac{1}{32}

Solution steps

Rewrite

y = - 8 x^{2}

in the standard form:

4 (- \frac{1}{32}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{32})

Refine

y = \frac{1}{32}

y = + (x + 5)^{2} + 3

(y + 6)^{2} = \frac{15}{11} (x + 12)

(y + 6)^{2} = 9 (x - 1)

y^{2} + 10 x = 0

y = - \frac{1}{2} (x + 6)^{2} + 8