What is the directrix (x^2)/9 ?

The directrix (x^2)/9 is y=-9/4

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directrix (x^2)/9

directrix

\frac{x ^{2}}{9}

y = - \frac{9}{4}

Solution steps

Rewrite

y = \frac{x ^{2}}{9}

in the standard form:

4 \cdot \frac{9}{4} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{9}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{9}{4}

Refine

y = - \frac{9}{4}

x^{2} + 36

y^{2} - 12 x - 2 y - 25 = 0

y = \frac{1}{4} (x - 1)^{2} - 2

25 x^{2} - 10 x - 200 y - 119 = 0

(y - 2)^{2} = - x - 3