What is the directrix y=(3x-4)(4x-3)-2x ?

The directrix y=(3x-4)(4x-3)-2x is y=-77/24

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directrix y=(3x-4)(4x-3)-2x

directrix

y = (3 x - 4) (4 x - 3) - 2 x

y = - \frac{77}{24}

Solution steps

Rewrite

y = (3 x - 4) (4 x - 3) - 2 x

in the standard form

4 \cdot \frac{1}{48} (y - (- \frac{51}{16})) = (x - \frac{9}{8})^{2}

(h, k) = (\frac{9}{8}, - \frac{51}{16}), p = \frac{1}{48}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{9}{8}, - \frac{51}{16})

y-coordinate

y = - \frac{51}{16} - p

y = - \frac{51}{16} - \frac{1}{48}

Refine

y = - \frac{77}{24}

y = x^{2} + 4 x + 4

y = - x^{2} + 5

y = - x^{2} + 10 x

y = x^{2} + 3

y = x^{2} + 1

What is the directrix y=(3x-4)(4x-3)-2x ?
The directrix y=(3x-4)(4x-3)-2x is y=-77/24