What is the directrix 2y^2-8x=0 ?

The directrix 2y^2-8x=0 is x=-1

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directrix 2y^2-8x=0

directrix

2 y^{2} - 8 x = 0

x = - 1

Solution steps

Rewrite

2 y^{2} - 8 x = 0

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 1

Refine

x = - 1

y = \frac{1}{4} x^{2}

y = 2 x^{2} - 2

y = 4 x^{2} + 8 x - 20

2 x^{2} - 4 x + 15

y = - \frac{1}{8} x^{2}