What is the directrix y^2+8x=0 ?

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directrix y^2+8x=0

directrix

y^{2} + 8 x = 0

x = 2

Solution steps

Rewrite

y^{2} + 8 x = 0

in the standard form:

4 (- 2) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 2)

Refine

x = 2

y = 2 x^{2} - 4 x + 15

x^{2} + 6 x + 8 y = 7

y = x^{2} - 6 x - 1

y^{2} + 6 y + 8 x + 25 = 0

y = x^{2} + 2 x + 3