What is the directrix 2x^2+3 ?

The directrix 2x^2+3 is y= 23/8

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directrix 2x^2+3

directrix

2 x^{2} + 3

y = \frac{23}{8}

Solution steps

Rewrite

y = 2 x^{2} + 3

in the standard form:

4 \cdot \frac{1}{8} (y - 3) = (x - 0)^{2}

(h, k) = (0, 3), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 3)

y-coordinate

y = 3 - p

y = 3 - \frac{1}{8}

Refine

y = \frac{23}{8}

x^{2} + x + 1

4 + 2 x - x^{2}

\frac{1}{4} x^{2} + x - 8

x^{2} - 8 x - 240

- 2 x^{2} - 4 x + 34