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Popular >

foci 3y^2=16x

Solution

foci

3 y^{2} = 16 x

Solution

(\frac{4}{3}, 0)

Solution steps

Rewrite

3 y^{2} = 16 x

in the standard form:

4 \cdot \frac{4}{3} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{4}{3}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + \frac{4}{3}, 0)

Refine

(\frac{4}{3}, 0)

Popular Examples

foci 9x^2+24x+72y+16=0 foci

9 x^{2} + 24 x + 72 y + 16 = 0

foci y=8(x+2)^2-1 foci

y = 8 (x + 2)^{2} - 1

foci x^2+2x+7 foci

x^{2} + 2 x + 7

foci x^2+2x+5 foci

x^{2} + 2 x + 5

foci x^2+2x+1 foci

x^{2} + 2 x + 1

Frequently Asked Questions (FAQ)

What is the foci 3y^2=16x ?
The foci 3y^2=16x is (4/3 ,0)