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Popular >

foci y=-10x^2

Solution

foci

y = - 10 x^{2}

Solution

(0, - \frac{1}{40})

Solution steps

Rewrite

y = - 10 x^{2}

in the standard form:

4 (- \frac{1}{40}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{40}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- \frac{1}{40}))

Refine

(0, - \frac{1}{40})

Popular Examples

foci (y+1)^2+3 foci

(y + 1)^{2} + 3

foci (x-5)^2=16(y+3)foci

(x - 5)^{2} = 16 (y + 3)

foci y=28x^2+47x+15 foci

y = 28 x^{2} + 47 x + 15

foci y=x^2-4x+4 foci

y = x^{2} - 4 x + 4

foci y^2+36x=0 foci

y^{2} + 36 x = 0

Frequently Asked Questions (FAQ)

What is the foci y=-10x^2 ?
The foci y=-10x^2 is (0,-1/40)