What is the foci (x-3)^2=y-7 ?

The foci (x-3)^2=y-7 is (3, 29/4)

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foci (x-3)^2=y-7

foci

(x - 3)^{2} = y - 7

(3, \frac{29}{4})

Solution steps

Rewrite

(x - 3)^{2} = y - 7

in the standard form:

4 \cdot \frac{1}{4} (y - 7) = (x - 3)^{2}

(h, k) = (3, 7), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, 7)

along the y-axis

(3, 7 + p)

= (3, 7 + \frac{1}{4})

Refine

(3, \frac{29}{4})

- 3 x^{2} + 5 x

(x - 1)^{2} = - 2 y - 11

(x + 3)^{2} = 12 (y - 5)

x^{2} - 6 x

x^{2} - 3 x