en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 3y^2+12x=0

Solution

foci

3 y^{2} + 12 x = 0

Solution

(- 1, 0)

Solution steps

Rewrite

3 y^{2} + 12 x = 0

in the standard form:

4 (- 1) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 1

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- 1), 0)

Refine

(- 1, 0)

Popular Examples

foci 3x^2+4 foci

3 x^{2} + 4

foci 3x^2+1 foci

3 x^{2} + 1

foci 3x^2+2 foci

3 x^{2} + 2

foci y= 2/(3.3)x^2-4x+6.6 foci

y = \frac{2}{3.3} x^{2} - 4 x + 6.6

foci-3x^2+5x-4 foci

- 3 x^{2} + 5 x - 4

Frequently Asked Questions (FAQ)

What is the foci 3y^2+12x=0 ?
The foci 3y^2+12x=0 is (-1,0)