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Popular >

foci 4y^2=x

Solution

foci

4 y^{2} = x

Solution

(\frac{1}{16}, 0)

Solution steps

Rewrite

4 y^{2} = x

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + \frac{1}{16}, 0)

Refine

(\frac{1}{16}, 0)

Popular Examples

foci y=3x^2-30x+77 foci

y = 3 x^{2} - 30 x + 77

foci (x+2)^2=-12(y-5)foci

(x + 2)^{2} = - 12 (y - 5)

foci y=2x^2-1-(5x-6)foci

y = 2 x^{2} - 1 - (5 x - 6)

foci (x-3)^2=8(y+1)foci

(x - 3)^{2} = 8 (y + 1)

foci 2x^2-8x+5 foci

2 x^{2} - 8 x + 5

Frequently Asked Questions (FAQ)

What is the foci 4y^2=x ?
The foci 4y^2=x is (1/16 ,0)