What is the foci y=3x^2+2 ?

The foci y=3x^2+2 is (0, 25/12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=3x^2+2

foci

y = 3 x^{2} + 2

(0, \frac{25}{12})

Solution steps

Rewrite

y = 3 x^{2} + 2

in the standard form:

4 \cdot \frac{1}{12} (y - 2) = (x - 0)^{2}

(h, k) = (0, 2), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 2)

along the y-axis

(0, 2 + p)

= (0, 2 + \frac{1}{12})

Refine

(0, \frac{25}{12})

y = 3 x^{2} + 19 x - 40

(y - 3)^{2} + 24 (x + 2) = 0

2 x^{2}

- 2 x^{2} - 2 x - 2

y = x^{2} + 3 x - 1