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Popular >

vertices x=-y^2

Solution

vertices

x = - y^{2}

Solution

(h, k) = (0, 0), p = - \frac{1}{4}

Solution steps

x = - y^{2}

Rewrite

x = - y^{2}

in the standard form:

4 (- \frac{1}{4}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{4}

Popular Examples

vertices f(x)=-x^2-8x-7 vertices

f (x) = - x^{2} - 8 x - 7

vertices 4x^2-3x+5 vertices

4 x^{2} - 3 x + 5

vertices f(x)=5x+3x^2-4 vertices

f (x) = 5 x + 3 x^{2} - 4

vertices f(x)=x^2+40x+20 vertices

f (x) = x^{2} + 40 x + 20

vertices f(x)=-x^2+4x+7 vertices

f (x) = - x^{2} + 4 x + 7

Frequently Asked Questions (FAQ)

What is the vertices x=-y^2 ?
The vertices x=-y^2 is (h,k)=(0,0),p=-1/4