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Popular >

vertices y^2-8x=0

Solution

vertices

y^{2} - 8 x = 0

Solution

(h, k) = (0, 0), p = 2

Solution steps

y^{2} - 8 x = 0

Rewrite

y^{2} - 8 x = 0

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 2

Popular Examples

vertices f(x)=-x^2+8x-15 vertices

f (x) = - x^{2} + 8 x - 15

vertices y=x^2+6 vertices

y = x^{2} + 6

vertices y=x^2+2 vertices

y = x^{2} + 2

vertices x^2+2x-8 vertices

x^{2} + 2 x - 8

vertices f(x)=3x^2-2x+1 vertices

f (x) = 3 x^{2} - 2 x + 1

Frequently Asked Questions (FAQ)

What is the vertices y^2-8x=0 ?
The vertices y^2-8x=0 is (h,k)=(0,0),p=2