What is the vertices y=-2x^2-4x-1 ?

The vertices y=-2x^2-4x-1 is Maximum (-1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y=-2x^2-4x-1

vertices

y = - 2 x^{2} - 4 x - 1

Maximum (- 1, 1)

Solution steps

y = - 2 x^{2} - 4 x - 1

The parabola parameters are:

a = - 2, b = - 4, c = - 1

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 4 )}{2 ( - 2 )}

Simplify

x_{v} = - 1

Plug in

x_{v} = - 1

to find the

y_{v}

value

y_{v} = 1

Therefore the parabola vertex is

(- 1, 1)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 2

Maximum (- 1, 1)

10 y^{2} = 22 x

2 x^{2} + 5 x - 7

x^{2} + 12 y = 0

- 4.9 t^{2} + 9.8 t

- x^{2} + 4 x + 3