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Popular >

vertices y^2=20x

Solution

vertices

y^{2} = 20 x

Solution

(h, k) = (0, 0), p = 5

Solution steps

y^{2} = 20 x

Rewrite

y^{2} = 20 x

in the standard form:

4 \cdot 5 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 5

Popular Examples

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y = 3 x^{2}

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- 12 x^{2} - 29 x + 230

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f (x) = 3 x^{2} - 6 x + 5

vertices 2x^2+4x-6 vertices

2 x^{2} + 4 x - 6

vertices y=k(x-0)^2+2 vertices

y = k (x - 0)^{2} + 2

Frequently Asked Questions (FAQ)

What is the vertices y^2=20x ?
The vertices y^2=20x is (h,k)=(0,0),p=5