What is ((y-7)^2)/(64)-((x-3)^2)/(16)=1 ?

The solution to ((y-7)^2)/(64)-((x-3)^2)/(16)=1 is Hyperbola with (h,k)=(3,7),a=8,b=4

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((y-7)^2)/(64)-((x-3)^2)/(16)=1

\frac{( y - 7 ) ^{2}}{64} - \frac{( x - 3 ) ^{2}}{16} = 1

(h, k) = (3, 7), a = 8, b = 4

Solution steps

\frac{( y - 7 ) ^{2}}{64} - \frac{( x - 3 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 7 ) ^{2}}{64} - \frac{( x - 3 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 7 ) ^{2}}{8 ^{2}} - \frac{( x - 3 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 7), a = 8, b = 4

4 y^{2} - 9 x^{2} - 36 x + 8 y - 68 = 0

x^{2} - y^{2} = 7

2 x^{2} - 8 y^{2} - 12 = 0

3 x^{2} - 2 y^{2} = 1

10 x^{2} - 25 y^{2} = 100

What is ((y-7)^2)/(64)-((x-3)^2)/(16)=1 ?
The solution to ((y-7)^2)/(64)-((x-3)^2)/(16)=1 is Hyperbola with (h,k)=(3,7),a=8,b=4