What is the eccentricity 2x^2+y^2=1 ?

The eccentricity 2x^2+y^2=1 is 1/(sqrt(2))

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eccentricity 2x^2+y^2=1

eccentricity

2 x^{2} + y^{2} = 1

\frac{1}{2}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

2 x^{2} + y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 1, a = \frac{1}{2}

= \frac{1 ^{2} - ( \frac{1}{2} ) ^{2}}{1}

\frac{1 ^{2} - ( \frac{1}{2} ) ^{2}}{1} = \frac{1}{2}

= \frac{1}{2}

\frac{8 x ^{2}}{1} + \frac{14 y ^{2}}{1} = 122

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

\frac{( x - 4 ) ^{2}}{5} + \frac{( y - 2 ) ^{2}}{4} = 1

49 x^{2} - 98 x + 64 y^{2} + 256 y - 2831 = 0

What is the eccentricity 2x^2+y^2=1 ?
The eccentricity 2x^2+y^2=1 is 1/(sqrt(2))