What is the eccentricity x^2+y^2+6x-4y-3=0 ?

The eccentricity x^2+y^2+6x-4y-3=0 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity x^2+y^2+6x-4y-3=0

eccentricity

x^{2} + y^{2} + 6 x - 4 y - 3 = 0

0

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

x^{2} + y^{2} + 6 x - 4 y - 3 = 0 :

Ellipse with center

(h, k) = (- 3, 2), b = 4, a = 4

= \frac{4 ^{2} - 4 ^{2}}{4}

\frac{4 ^{2} - 4 ^{2}}{4} = 0

= 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

4 x^{2} + y^{2} = 16

x^{2} + y^{2} - 6 x - 8 y = 50

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1

\frac{x ^{2}}{4} + y^{2} = 1

What is the eccentricity x^2+y^2+6x-4y-3=0 ?
The eccentricity x^2+y^2+6x-4y-3=0 is 0