What is the center ((x+5)^2)/(49)+((y-2)^2)/(81)=1 ?

The center ((x+5)^2)/(49)+((y-2)^2)/(81)=1 is (-5,2)

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center ((x+5)^2)/(49)+((y-2)^2)/(81)=1

center

\frac{( x + 5 ) ^{2}}{49} + \frac{( y - 2 ) ^{2}}{81} = 1

(- 5, 2)

Solution steps

\frac{( x + 5 ) ^{2}}{49} + \frac{( y - 2 ) ^{2}}{81} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{49} + \frac{( y - 2 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{7 ^{2}} + \frac{( y - 2 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, 2), a = 7, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 5, 2), b = 9, a = 7

And the center is:

(- 5, 2)

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{36} = 1

\frac{x ^{2}}{4} + y^{2} = 1

5 x^{2} + 9 y^{2} - 10 x + 4 = 0

3 x^{2} + 4 y^{2} = 12

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

What is the center ((x+5)^2)/(49)+((y-2)^2)/(81)=1 ?
The center ((x+5)^2)/(49)+((y-2)^2)/(81)=1 is (-5,2)