What is the vertices x^2+y^2-10y=0 ?

The vertices x^2+y^2-10y=0 is (0,10),(0,0)

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vertices x^2+y^2-10y=0

vertices

x^{2} + y^{2} - 10 y = 0

(0, 10), (0, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

x^{2} + y^{2} - 10 y = 0 :

Ellipse with center

(h, k) = (0, 5), b = 5, a = 5

(0, 5 + 5), (0, 5 - 5)

Refine

(0, 10), (0, 0)

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\frac{( x - 3 ) ^{2}}{25} + (y - 2)^{2} = 1

x^{2} + 4 y^{2} + 2 x - 12 y + 6 = 0