What is the vertices x^2+3y^2-6x+6y=0 ?

The vertices x^2+3y^2-6x+6y=0 is (3+2sqrt(3),-1),(3-2sqrt(3),-1)

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vertices x^2+3y^2-6x+6y=0

vertices

x^{2} + 3 y^{2} - 6 x + 6 y = 0

(3 + 23, - 1), (3 - 23, - 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 3 y^{2} - 6 x + 6 y = 0 :

Ellipse with center

(h, k) = (3, - 1), a = 23, b = 2

(3 + 23, - 1), (3 - 23, - 1)

7 x^{2} + 9 y^{2} = 63

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

300 x^{2} + 150 y^{2} = 50

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

What is the vertices x^2+3y^2-6x+6y=0 ?
The vertices x^2+3y^2-6x+6y=0 is (3+2sqrt(3),-1),(3-2sqrt(3),-1)