What is the vertices 9x^2+36x+y^2+2y+36=0 ?

The vertices 9x^2+36x+y^2+2y+36=0 is (-2,0),(-2,-2)

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vertices 9x^2+36x+y^2+2y+36=0

vertices

9 x^{2} + 36 x + y^{2} + 2 y + 36 = 0

(- 2, 0), (- 2, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 36 x + y^{2} + 2 y + 36 = 0 :

Ellipse with center

(h, k) = (- 2, - 1), b = 1, a = \frac{1}{3}

(- 2, - 1 + 1), (- 2, - 1 - 1)

Refine

(- 2, 0), (- 2, - 2)

27 x^{2} + y^{2} - 18 y = 0

\frac{( x - 2 ) ^{2}}{5} + \frac{( y + 3 ) ^{2}}{9} = 1

25 x^{2} + y^{2} - 4 y - 21 = 0

9 x^{2} - 72 x + y^{2} + 4 y + 112 = 0

4 x^{2} + 9 y^{2} = 1

What is the vertices 9x^2+36x+y^2+2y+36=0 ?
The vertices 9x^2+36x+y^2+2y+36=0 is (-2,0),(-2,-2)